Correct, you only want a newline at the end of each line.
You will want a 'puts' outside of the inner loop.
n = 1
while n <= 5
1.upto(n) do |i|
print "#{i} "
end
puts
n += 1
end
From: Jaimin Pandya <lists@ruby-forum.com>
To: ruby-talk@ruby-lang.org
Date: 02/27/2014 07:55 AM
Subject: Re: How to do pattern program in Ruby?
Sent by: "ruby-talk" <ruby-talk-bounces@ruby-lang.org>
Panagiotis Atmatzidis wrote in post #1138192:
> Hey again,
>
> Sorry for the previous mail, was out of line, you have the code
there...
···
"ruby-talk" <ruby-talk-bounces@ruby-lang.org> wrote on 02/27/2014 07:55:01 AM:
> and I'm terribly sleepy.
>>
>> I am trying to do as follow:
>>
>> n = 1
>> while n <= 5
>> 1.upto(n) do |i|
>> print "#{i} "
>
> Just add the "\n" (newline) and you're all set: print "#{i}\n"
>
By adding "\n" , i am not able to get desire output.
I would not have thought of using string indexing like that.
I prefer not having the hard coded maximum string.
How about this, the max is variable and it centers the rows.
max = 6
1.upto(max) do |i|
line = ""
i.downto(1) {|j| line += "#{j} "}
puts line.rjust(max + i)
end
···
"ruby-talk" <ruby-talk-bounces@ruby-lang.org> wrote on 02/24/2014 02:11:33 PM:
From: Regis d'Aubarede <lists@ruby-forum.com>
To: ruby-talk@ruby-lang.org
Date: 02/24/2014 02:12 PM
Subject: Re: How to do pattern program in Ruby?
Sent by: "ruby-talk" <ruby-talk-bounces@ruby-lang.org>
Jaimin Pandya wrote in post #1137859:
>> Jaimin Pandya wrote in post #1137849:
> can I do that?
Yes you (should) can...
n = 1
while n < 6
puts "6 5 4 3 2 1"[2*(6-n)..12]
n += 1
end
