How can I invoke super class's method

ruby-talk
1

My class include a Module and overwrite a method of the Module. In this
method, I want to invoke the Module's method first. Just like
"super.method()" in Java. How can I do this?

···

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2

Zhao Yi wrote:

My class include a Module and overwrite a method of the Module. In this
method, I want to invoke the Module's method first. Just like
"super.method()" in Java. How can I do this?

Just the word super().
module M
  def q(arg)

···

#
  end
end
class K
  include M
  def q(arg)
    #
    super(arg)
  end
end

super() calls ancestor's function with the same name as the function
you're currently in.

TPR.
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3

Hi --

Zhao Yi wrote:

My class include a Module and overwrite a method of the Module. In this
method, I want to invoke the Module's method first. Just like
"super.method()" in Java. How can I do this?

Just the word super().
module M
def q(arg)
   #
end
end
class K
include M
def q(arg)
   #
   super(arg)
end
end

super() calls ancestor's function with the same name as the function
you're currently in.

Keep in mind, though, that the semantics of super (which is a keyword,
rather than a method) are a bit different from regular method-calling
semantics:

   super # call ancestor's method with current arguments
   super(a,b) # call with exactly the arguments (a,b)
   super() # call with no arguments

It's really the first one that's the special case, as you can see.

David

···

On Sun, 31 Aug 2008, Thomas B. wrote:

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4

Got it thanks.

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