Hi everyone,
So I am new to ruby, and I need help for a regexp.
I want to stock the letter and the number in this sting "e = 11.1607"
I tried with this regexp:
/(?<letter>^\w+)\/(?<frequency>\d{1,2}.\d+)/
But it does not match anything... But I tried separatly and it returns
me the good things. I do not understand what's the problem ^^'
Thank you to everyone who gonna help me ! 
--
Posted via http://www.ruby-forum.com/.
Hi,
Quentin RG wrote in post #1066270:
/(?<letter>^\w+)\/(?<frequency>\d{1,2}.\d+)/
But it does not match anything... But I tried separatly and it returns
me the good things. I do not understand what's the problem ^^'
I don't know how you've come to the "\/" part of the regex. This makes
the regex match only strings with some word characters followed by a
slash followed by some digits. For example the string "e/12.1516".
I think you rather want "\s*=\s*" instead of the "\/" (an equals sign
between spaces).
By the way: The dot "." has to be escaped. Otherwise it will match *any*
character except newlines. And I think you should replace the "\w" with
alphabetic characters: "[A-Za-z]". Because the \w also matches digits
and the underscore.
--
Posted via http://www.ruby-forum.com/\.
This works for me. Note that the start anchor "^" is outside of the
group, and that between both groups you need to match spaces and "=".
Also the "." has to be escaped to be matched exactly, otherwise it's
any character:
1.9.2p290 :026 > m = string.match
/^(?<letter>\w+)\s*=\s*(?<frequency>\d{1,2}\.\d+)/
=> #<MatchData "e = 11.1607" letter:"e" frequency:"11.1607">
1.9.2p290 :030 > m.names
=> ["letter", "frequency"]
1.9.2p290 :031 > m["letter"]
=> "e"
1.9.2p290 :032 > m["frequency"]
=> "11.1607"
Jesus.
On Wed, Jun 27, 2012 at 9:24 AM, Quentin R-G <lists@ruby-forum.com> wrote:
Hi everyone,
So I am new to ruby, and I need help for a regexp.
I want to stock the letter and the number in this sting "e = 11.1607"I tried with this regexp:
/(?<letter>^\w+)\/(?<frequency>\d{1,2}.\d+)/
But it does not match anything... But I tried separatly and it returns
me the good things. I do not understand what's the problem ^^'Thank you to everyone who gonna help me !
Okay, thank you guys for your help and advices 
It works now!
--
Posted via http://www.ruby-forum.com/.
Even better, use [[:alpha:]]+ so that the expression also matches accented and foreign alphabetic characters.
"déjà vu".scan(/\w+/)
=> ["d", "j", "vu"]
"déjà vu".scan(/[[:alpha:]]+/)
=> ["déjà ", "vu"]
On 06/27/2012 09:34 AM, Jan E. wrote:
Quentin RG wrote in post #1066270:
/(?<letter>^\w+)\/(?<frequency>\d{1,2}.\d+)/
And I think you should replace the "\w" with alphabetic characters:
"[A-Za-z]". Because the \w also matches digits
--
Lars Haugseth
In the future you should check out rubular.com. It's always my first stop
when I'm working with regexes.
On Jun 27, 2012 3:58 AM, "Quentin RG" <lists@ruby-forum.com> wrote:
Okay, thank you guys for your help and advices
It works now!--
Posted via http://www.ruby-forum.com/\.
