Hash of Hash to Arr

Hi!

How an I convert a Hash of Hashes to a array (table) (and vice versa)?
h[k1][k2][k3]... = value <=> a[i] = [k1,k2,k3,value]
#CORRECTION: (variable count of keys):
h[k1][k2][k3]... = value <=> a[i] = [k1,k2,k3,.., value] # (
or if you prefer: [value, [k1,...,kn]] )
#k1,k2,k3 = vars vor (many) keys;
# h.recursive_keys.flatten.length == a.length

- hoping s.o. understands, what I'm meaning

thank you
Opti

## just one answer, in the case I don't get any! :wink:

This seemed to work for me.

def convert_to_arrays(hash)
  convert_to_array(hash).flatten(depth_of_hash(hash))
end

def depth_of_hash(hash)
  depth = -1
  object = hash
  begin
    object = object.values.first
    depth +=1
  end while object.is_a?(Hash)
  depth
end

def convert_to_array(hash, keys = [])
  hash.map do |key, value|
    if value.is_a?(Hash)
      convert_to_array(value, keys + [key])
    else
      keys + [key, value]
    end
  end
end

h1 = {a: {b: {c: 1, d: 2}, e: {f: 3, g: 4}}, h: {i: {j: 5}}}
h2 = {b: {c: 1, d: 2}, e: {f: 3, g: 4}, i: {j: 5}}

p h1
p convert_to_arrays(h1)

p h2
p convert_to_arrays(h2)

Cheers,

···

On Mon, Aug 9, 2021 at 8:12 AM Die Optimisten <inform@die-optimisten.net> wrote:

Hi!

How an I convert a Hash of Hashes to a array (table) (and vice versa)?
   h[k1][k2][k3]... = value <=> a[i] = [k1,k2,k3,value]
#CORRECTION: (variable count of keys):
   h[k1][k2][k3]... = value <=> a[i] = [k1,k2,k3,.., value] # (
or if you prefer: [value, [k1,...,kn]] )
    #k1,k2,k3 = vars vor (many) keys;
    # h.recursive_keys.flatten.length == a.length

   - hoping s.o. understands, what I'm meaning

thank you
Opti

## just one answer, in the case I don't get any! :wink:

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Andy Maleh