Hash name increment on iteration?

ruby-talk
1

Is it possible to add to the name of a hash while running through an
iteration? What I'm trying to achieve:

SomeArray.each do |i, name, content|
  info[i+1] = { "name" => name, "content" => content }
end

So that I can call, for example info[1] [name] or info[5][content]...

2

Make info an Array and just use

info << { :name => name, :content => content }

Kind regards

  robert

···

On 08.04.2010 03:27, Shaz wrote:

Is it possible to add to the name of a hash while running through an
iteration? What I'm trying to achieve:

SomeArray.each do |i, name, content|
   info[i+1] = { "name" => name, "content" => content }
end

So that I can call, for example info[1] [name] or info[5][content]...

--
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/

3

Is this what you want?

SomeArray.each_with_index do |(name,content),i|
  ...
end

···

--
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4

Each with index worked for me - didn't realize each variable in the
array has an index that can be called. Thanks!

···

On 8 Apr, 08:44, Brian Candler <b.cand...@pobox.com> wrote:

Is this what you want?

SomeArray.each_with_index do |(name,content),i|
...
end

--
Posted viahttp://www.ruby-forum.com/.

5

Shaz wrote:

Each with index worked for me - didn't realize each variable in the
array has an index that can be called.

Not exactly. The 'each_with_index' method just yields the array index to
the block being called.

Inside it will be implemented something like this:

module Enumerable
  def each_with_index
    i = 0
    each do |elem|
      yield elem, i
      i += 1
    end
  end
end

But you could consider it like this:

class Array
  def each_with_index
    size.times do |i|
      yield self[i], i
    end
  end
end

···

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6

Brian Candler wrote:

Inside it will be implemented something like this:

module Enumerable
  def each_with_index
    i = 0
    each do |elem|
      yield elem, i
      i += 1
    end
  end
end

But you could consider it like this:

class Array
  def each_with_index
    size.times do |i|
      yield self[i], i
    end
  end
end

Hi Brian,

Just some follow-up questions for these codes:
I recall the the method call in Ruby follow this format:
"receiver.method"
So
1) which one is the reciever for "each"?
2) which one is the reciever for "size"?

Thanks,

Li

···

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7

When there's no explicit receiver, the method call happens on the
object that is "self" at that point.

Jesus.

···

On Sun, Apr 11, 2010 at 5:32 PM, Li Chen <chen_li3@yahoo.com> wrote:

Brian Candler wrote:

Inside it will be implemented something like this:

module Enumerable
def each_with_index
i = 0
each do |elem|
yield elem, i
i += 1
end
end
end

But you could consider it like this:

class Array
def each_with_index
size.times do |i|
yield self[i], i
end
end
end

Hi Brian,

Just some follow-up questions for these codes:
I recall the the method call in Ruby follow this format:
"receiver.method"
So
1) which one is the reciever for "each"?
2) which one is the reciever for "size"?

8

Jesús Gabriel y Galán wrote:

···

On Sun, Apr 11, 2010 at 5:32 PM, Li Chen <chen_li3@yahoo.com> wrote:

� � end
� end

1) which one is the reciever for "each"?
2) which one is the reciever for "size"?

When there's no explicit receiver, the method call happens on the
object that is "self" at that point.

Jesus.

Hi Gabriel,

Where can I find more info about method call on implicit receiver?

Li

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Posted via http://www.ruby-forum.com/\.

9

Seems like we've had a number of newbies who've been perplexed about
this recently. Maybe this should be in the faq. Isn't there a faq
somewhere?

···

On 4/11/10, Li Chen <chen_li3@yahoo.com> wrote:

Where can I find more info about method call on implicit receiver?