I'm having some trouble understanding how hashes work in Ruby. Consider
the following test :
irb(main):002:0> v=Vector[4,5]
=> Vector[4, 5]
irb(main):003:0> v2=Vector[4,5]
=> Vector[4, 5]
irb(main):004:0> v==v2
=> true
irb(main):005:0> v.hash
=> 17
irb(main):006:0> v2.hash
=> 17
irb(main):007:0> h=Hash.new
=> {}
irb(main):008:0> h[v]="whatever is in (4,5)"
=> "whatever is in (4,5)"
irb(main):009:0> h[v2]
=> nil
I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both
have the same hash value... what am I doing wrong?
···
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Sébastien Wautelet wrote:
I'm having some trouble understanding how hashes work in Ruby. Consider the following test :
irb(main):002:0> v=Vector[4,5]
=> Vector[4, 5]
irb(main):003:0> v2=Vector[4,5]
=> Vector[4, 5]
irb(main):004:0> v==v2
=> true
irb(main):005:0> v.hash
=> 17
irb(main):006:0> v2.hash
=> 17
irb(main):007:0> h=Hash.new
=> {}
irb(main):008:0> h[v]="whatever is in (4,5)"
=> "whatever is in (4,5)"
irb(main):009:0> h[v2]
=> nil
I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both have the same hash value... what am I doing wrong?
It's not enough that they have the same hash value or that obj1 == obj2. For the purposes of Hash, two objects are the same if obj1.eql?(obj2). Does v1.eql?(v2)?
Sébastien Wautelet wrote:
I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both
have the same hash value... what am I doing wrong?
Hash keys can be any object. So your hash, h, has one key, the object v.
Take another hash real quick, we'll call it hash.
hash = Hash.new
hash['rabbit'] = 'cute' # 'cute'
hash['blue'] # nil
The value for any hash key not defined is nil (unless you explicitly
tell the hash during instantiation to use another value).
So just because you're using the value of v as a key in your hash, does
not mean that v2 is automatically another key in your hash.
···
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I think you're getting hung up on this part:
Sébastien Wautelet wrote:
irb(main):004:0> v==v2
=> true
Yes, v and v2 are equal. But that is irrelevant with regards to your
hash.
Now, if you had to objects that were identical (not equal, but
identical) then it would work:
s1 = 'string'
s2 = s1
h = Hash.new
h[s1] # 'string'
h[s2] # 'string'
s1.upcase!
h[s2] # 'STRING'
h[s1] # 'STRING'
Hope that helps.
···
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Timothy Hunter wrote:
Sébastien Wautelet wrote:
I'm having some trouble understanding how hashes work in Ruby. Consider the following test :
irb(main):002:0> v=Vector[4,5]
=> Vector[4, 5]
irb(main):003:0> v2=Vector[4,5]
=> Vector[4, 5]
irb(main):004:0> v==v2
=> true
irb(main):005:0> v.hash
=> 17
irb(main):006:0> v2.hash
=> 17
irb(main):007:0> h=Hash.new
=> {}
irb(main):008:0> h[v]="whatever is in (4,5)"
=> "whatever is in (4,5)"
irb(main):009:0> h[v2]
=> nil
I'd have expected h[v2] => "whatever is in (4,5)", since v==v2 and both have the same hash value... what am I doing wrong?
It's not enough that they have the same hash value or that obj1 == obj2. For the purposes of Hash, two objects are the same if obj1.eql?(obj2). Does v1.eql?(v2)?
Testing reveals that they don't. but that strikes me as a bug in the Vector class. It violates the guidelines given in the PickAxe book (bottom of page 568), and more importantly, it violates common intuition. If two vectors that are created in exactly the same manner aren't eql?, they're useless for use as hash keys. I'd say file a bug report, or at least a problem, on this one.
Cheers,
Ken
Daniel Waite wrote:
I think you're getting hung up on this part:
Sébastien Wautelet wrote:
> irb(main):004:0> v==v2
> => true
Yes, v and v2 are equal. But that is irrelevant with regards to your
hash.
Now, if you had to objects that were identical (not equal, but
identical) then it would work:
I think it is relevant, given that the Vector class is designed to be
immutable. I would agree that the Vector class should probably define
#eql? as an alias for #==.
It appears to be a typo in Matrix.rb - This is in ruby1.8.4:
class Vector
...
···
On 10/13/06, Phrogz <gavin@refinery.com> wrote:
I think it is relevant, given that the Vector class is designed to be
immutable. I would agree that the Vector class should probably define
#eql? as an alias for #==.
#
# Returns +true+ iff the two vectors have the same elements in the same order.
#
def ==(other)
return false unless Vector === other
other.compare_by(@elements)
end
alias eqn? ==
~~~
And Vector seems to be the only implementor of eqn?
rick@frodo:~/ruby-1.8.4$ ri eqn
------------------------------------------------------------ Vector#eqn?
eqn?(other)
------------------------------------------------------------------------
Alias for #==
And it's not yet fixed in 1.9
rick@frodo:~/ruby-1.8.4$ grep eqn /public/rubysource/ruby1.9/ruby/lib/matrix.rb
alias eqn? ==
--
Rick DeNatale
My blog on Ruby
http://talklikeaduck.denhaven2.com/