Hello I'm new here 
And I already have a noob question.
I am wondering how it's possible to iterate through a for loop statement
by 5 rather than by 1.
Let's suppose I want to count from 0..100.
Rather than doing this:
1,2,3,4,5,6,7,8,9,10....97, 98, 99, 100
I would like to count by 5 like this:
0, 5, 10, 15, 20, 25, 30... 90, 95, 100
Anyone knoew how I could achieve this?
Thank you very much in advance!
And nice to meet you 
ยทยทยท
--
Posted via http://www.ruby-forum.com/.
Hi there,
If you're on Ruby 1.8.7 or Ruby 1.9+, you can use the Range class's "step" method
with either a for loop, or with blocks:
for x in (0..100).step(5)
puts x
end
or
(0..100).step(5) do |x|
puts x
end
You can equivalently do 0.step(100, 5) in place of (0..100).step(5) โ they're equivalent.
If you're on an older version of Ruby, you may only be able to use the second version there -
I don't have an older copy ready to check that though.
Not many rubyists use the for loop these days because it has a couple quirks, but
they probably won't trip up a beginner.
To find out more, check out the Range class: class Range - RDoc Documentation
Good luck!
Mike Edgar
http://carboni.ca/
ยทยทยท
On Feb 3, 2011, at 12:41 AM, Thescholar Thescholar wrote:
Hello I'm new here 
And I already have a noob question.
I am wondering how it's possible to iterate through a for loop statement
by 5 rather than by 1.
Let's suppose I want to count from 0..100.
Rather than doing this:
1,2,3,4,5,6,7,8,9,10....97, 98, 99, 100
I would like to count by 5 like this:
0, 5, 10, 15, 20, 25, 30... 90, 95, 100
Anyone knoew how I could achieve this?
Thank you very much in advance!
And nice to meet you 
--
Posted via http://www.ruby-forum.com/\.
botp1
(botp)
3
try this,
for i in (0..100).step(5)
p i
end
then compare this,
(0..100).step(5){|i| p i }
best regards -botp
ยทยทยท
On Thu, Feb 3, 2011 at 1:41 PM, Thescholar Thescholar <thescholar@hotmail.ca> wrote:
I am wondering how it's possible to iterate through a for loop statement
by 5 rather than by 1.
Thank you very much!
Your advices were very useful.
ยทยทยท
--
Posted via http://www.ruby-forum.com/.
Robert_K1
(Robert K.)
5
There is also Fixnum#step
irb(main):003:0> 0.step(100, 5) {|i| p i}
0
5
10
15
20
25
30
35
40
45
50
55
60
65
70
75
80
85
90
95
100
=> 0
irb(main):004:0>
Cheers
robert
ยทยทยท
On Thu, Feb 3, 2011 at 6:58 AM, botp <botpena@gmail.com> wrote:
On Thu, Feb 3, 2011 at 1:41 PM, Thescholar Thescholar > <thescholar@hotmail.ca> wrote:
I am wondering how it's possible to iterate through a for loop statement
by 5 rather than by 1.
try this,
for i in (0..100).step(5)
p i
end
then compare this,
(0..100).step(5){|i| p i }
--
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/