FasterCSV - Merge CSV

I have 3 CSVs with the same content with say 10 rows. There is a slight
variation to 1 column in the data it contains.

csv1 - 20 lines 10 cols
csv2 - 52 lines 10 cols
csv3 - 24 lines 10 cols

How can I merge all 3 csvs into 1 csv using fastercsv so I have

csv4 96 lines 10 cols

Thanks!

Seed

···

--
Posted via http://www.ruby-forum.com/.

Christian Smith wrote:

I have 3 CSVs with the same content with say 10 rows. There is a slight
variation to 1 column in the data it contains.

csv1 - 20 lines 10 cols
csv2 - 52 lines 10 cols
csv3 - 24 lines 10 cols

How can I merge all 3 csvs into 1 csv using fastercsv so I have

csv4 96 lines 10 cols

Thanks!

Seed

Why use fastercsv?
cat csv1 csv2 csv3 >csv4
would meet your requirement.

But if you want to use fastercsv, then open each file in turn, read it
line at a time, and output the line you just read.

···

--
Posted via http://www.ruby-forum.com/\.

Christian Smith wrote:

I have 3 CSVs with the same content with say 10 rows. There is a slight
variation to 1 column in the data it contains.

csv1 - 20 lines 10 cols
csv2 - 52 lines 10 cols
csv3 - 24 lines 10 cols

How can I merge all 3 csvs into 1 csv using fastercsv so I have

csv4 96 lines 10 cols

Thanks!

Seed

Why use fastercsv?
cat csv1 csv2 csv3 >csv4
would meet your requirement.

except that you'd have headers from csv2 and csv3 (but perhaps your line counts imply no headers?)

But if you want to use fastercsv, then open each file in turn, read it
line at a time, and output the line you just read.
--

If the files are small-ish, you can avoid a chicken-and-egg problem of the headers by reading all the input files (saving the headers from the first), then writing it all out from memory.

-Rob

Rob Biedenharn
Rob@AgileConsultingLLC.com http://AgileConsultingLLC.com/
rab@GaslightSoftware.com http://GaslightSoftware.com/

···

On Jul 2, 2010, at 7:11 AM, Brian Candler wrote:

Rob Biedenharn wrote:

csv4 96 lines 10 cols

Thanks!

Seed

Why use fastercsv?
cat csv1 csv2 csv3 >csv4
would meet your requirement.

except that you'd have headers from csv2 and csv3 (but perhaps your
line counts imply no headers?)

But if you want to use fastercsv, then open each file in turn, read it
line at a time, and output the line you just read.
--

If the files are small-ish, you can avoid a chicken-and-egg problem of
the headers by reading all the input files (saving the headers from
the first), then writing it all out from memory.

-Rob

Rob Biedenharn
Rob@AgileConsultingLLC.com http://AgileConsultingLLC.com/
rab@GaslightSoftware.com http://GaslightSoftware.com/

If the files are small-ish, you can avoid a chicken-and-egg problem of
the headers by reading all the input files (saving the headers from
the first), then writing it all out from memory.

The files aren't smallish but memory isn't an issue. I would love to be
able to do this. I am able to read the 3 files into an array but it's
parsing them back into 1 csv I am having trouble with. I would assume
this would be a lot faster than a line read>write approach.

···

On Jul 2, 2010, at 7:11 AM, Brian Candler wrote:

--
Posted via http://www.ruby-forum.com/\.

just cat and grep out the header lines

cat csv* |grep -v string-portion-unique-to-headers > full.csv

If you want to head a header row, then

cat csv* | grep string-portion-unique-to-headers |sort | uniq > full.csv
cat csv* | grep -v string-portion-unique-to-headers >> full.csv

···

On Sat, Jul 03, 2010 at 02:15:06AM +0900, Christian Smith wrote:

Rob Biedenharn wrote:
> On Jul 2, 2010, at 7:11 AM, Brian Candler wrote:
>>>
>>> csv4 96 lines 10 cols
>>>
>>> Thanks!
>>>
>>> Seed
>>
>> Why use fastercsv?
>> cat csv1 csv2 csv3 >csv4
>> would meet your requirement.
>
> except that you'd have headers from csv2 and csv3 (but perhaps your
> line counts imply no headers?)
>
>>
>> But if you want to use fastercsv, then open each file in turn, read it
>> line at a time, and output the line you just read.
>> --
>
> If the files are small-ish, you can avoid a chicken-and-egg problem of
> the headers by reading all the input files (saving the headers from
> the first), then writing it all out from memory.
>
> -Rob
>
> Rob Biedenharn
> Rob@AgileConsultingLLC.com http://AgileConsultingLLC.com/
> rab@GaslightSoftware.com http://GaslightSoftware.com/

If the files are small-ish, you can avoid a chicken-and-egg problem of
the headers by reading all the input files (saving the headers from
the first), then writing it all out from memory.

The files aren't smallish but memory isn't an issue. I would love to be
able to do this. I am able to read the 3 files into an array but it's
parsing them back into 1 csv I am having trouble with. I would assume
this would be a lot faster than a line read>write approach.

--
Posted via http://www.ruby-forum.com/\.

OK, let's read them all in and then write out one file...

headers = nil
all_rows =
input_files.each do |input_file|
  csv = FasterCSV.table(input_file, :headers => true)
  in_headers, *in_rows = csv.to_a
  headers ||= in_headers
  all_rows.concat(in_rows)
end
FasterCSV.open(output_file, 'w') do |csv|
   csv << headers
   all_rows.each {|row| csv << row }
end

The full example is at:
   combined.csv · GitHub

The details may have to change a bit depending on your circumstances, but the general idea is sound.

-Rob

Rob Biedenharn
Rob@AgileConsultingLLC.com http://AgileConsultingLLC.com/
rab@GaslightSoftware.com http://GaslightSoftware.com/

···

On Jul 2, 2010, at 1:15 PM, Christian Smith wrote:

Rob Biedenharn wrote:

On Jul 2, 2010, at 7:11 AM, Brian Candler wrote:

csv4 96 lines 10 cols

Thanks!

Seed

Why use fastercsv?
cat csv1 csv2 csv3 >csv4
would meet your requirement.

except that you'd have headers from csv2 and csv3 (but perhaps your
line counts imply no headers?)

But if you want to use fastercsv, then open each file in turn, read it
line at a time, and output the line you just read.
--

If the files are small-ish, you can avoid a chicken-and-egg problem of
the headers by reading all the input files (saving the headers from
the first), then writing it all out from memory.

-Rob

Rob Biedenharn
Rob@AgileConsultingLLC.com http://AgileConsultingLLC.com/
rab@GaslightSoftware.com http://GaslightSoftware.com/

If the files are small-ish, you can avoid a chicken-and-egg problem of
the headers by reading all the input files (saving the headers from
the first), then writing it all out from memory.

The files aren't smallish but memory isn't an issue. I would love to be
able to do this. I am able to read the 3 files into an array but it's
parsing them back into 1 csv I am having trouble with. I would assume
this would be a lot faster than a line read>write approach.

FasterCSV.open(output_file, 'w') do |ocsv|
  input_files.each_with_index do |input_file, i|
    FasterCSV.foreach(input_file, :headers => true, :return_headers =>
true) do |row|
      next if i > 0 and row.header_row?
      ocsv << row
    end
  end
end

···

On Fri, Jul 2, 2010 at 3:27 PM, Rob Biedenharn <Rob@agileconsultingllc.com> wrote:

OK, let's read them all in and then write out one file...

headers = nil
all_rows =
input_files.each do |input_file|
csv = FasterCSV.table(input_file, :headers => true)
in_headers, *in_rows = csv.to_a
headers ||= in_headers
all_rows.concat(in_rows)
end
FasterCSV.open(output_file, 'w') do |csv|
csv << headers
all_rows.each {|row| csv << row }
end