it's a newbie question...
i wanted to do something like:
result1 = [1, 2, 3].find { |e|
if e == 2
return true
else
return false
end
}
(with several if/else one in each other rather than one big condition, for
code readability)
but I realised that ‘return’ does not apply to a block, but only to a
function. it’s a bit (actually very) un-intuitive for me, but anyway, is
there a nicer solution than doing my current:
item = [1, 2, 3].find { |e|
result = false
if e == 2
result = true
else
result = false
end
result
}
for reference, here is my real code. I’m searching the current TV program at
showTime from a DB of tv programs i fetched from the net. a program for sure
has a start time (time), but not necessarily an end time (if it’s the last tv
program on the web page, i can’t know).
# now find the current program for this
# channel.
programsForChannel.find { |program|
result = false
if program.time <= showTime
if program.endTime
# there is a endtime.
# are we now before this end?
if program.endTime > showTime
result = true
end
else
# program has no registered
# end.
result = true
end
end
result
}
any help appreciated!
emmanuel
···
–
“If there is any kind of God, it’s not in you or in me,
but in the space between us”
– Celine, “Before Sunrise”
(It’s not about what you do, it’s about what you give.)
result1 = [1, 2, 3].find { |e|
if e == 2
return true
else
return false
end
}
(with several if/else one in each other rather than one big condition, for
code readability)
but I realised that ‘return’ does not apply to a block, but only to a
function. it’s a bit (actually very) un-intuitive for me, but anyway, is
there a nicer solution than doing my current:
If you switch to 1.8.0, there’s nicer way:
result = [1, 2, 3].find { |e|
if e == 2
break true
else
break false
end
}
it’s a newbie question…
i wanted to do something like:
result1 = [1, 2, 3].find { |e|
if e == 2
return true
else
return false
end
}
(with several if/else one in each other rather than one big condition,
for
code readability)
but I realised that ‘return’ does not apply to a block, but only to a
function. it’s a bit (actually very) un-intuitive for me, but anyway, is
there a nicer solution than doing my current:
item = [1, 2, 3].find { |e|
result = false
if e == 2
result = true
else
result = false
end
result
}
for reference, here is my real code. I’m searching the current TV
program at
showTime from a DB of tv programs i fetched from the net. a program for
sure
has a start time (time), but not necessarily an end time (if it’s the
last tv
program on the web page, i can’t know).
now find the current program for this
channel.
programsForChannel.find { |program|
result = false
if program.time <= showTime
if program.endTime
there is a endtime.
are we now before this end?
if program.endTime > showTime
result = true
end
else
program has no registered
end.
result = true
end
end
result
}
any help appreciated!
In your case you can use “return” even with older versions of ruby if you
use a method:
def find
[1, 2, 3].find { |e|
return true if e == 2
}
false
end
Are you aware of the standard methods Enumerable#include?,
Enumerable#find, Enumerable#detect, Enumerable#select, Enumerable#find_all
and Enumerable#grep? These should provide the functionality you need.
At Mon, 26 May 2003 15:30:28 +0900, Emmanuel Touzery wrote:
now find the current program for this
channel.
programsForChannel.find { |program|
result = false
if program.time <= showTime
if program.endTime
# there is a endtime.
# are we now before this end?
if program.endTime > showTime
result = true
end
else
# program has no registered
# end.
result = true
end
end
result
}
it’s a newbie question…
i wanted to do something like:
result1 = [1, 2, 3].find { |e|
if e == 2
return true
else
return false
end
}
(with several if/else one in each other rather than one big condition, for
code readability)
Can’t you just do:
[1, 2, 3].find{|e|
if e == 2
true
else
false
end
}
? You can nest several if-else-blocks inside if you want, with each
block returning the last statement…
I think I understood your problem, but ignore me if this is not what
you’re seeking
it’s a newbie question…
i wanted to do something like:
result1 = [1, 2, 3].find { |e|
if e == 2
return true
else
return false
end
}
(with several if/else one in each other rather than one big condition,
for
code readability)
Can’t you just do:
[1, 2, 3].find{|e|
if e == 2
true
else
false
end
}
If you’re proposoing a simplification then why not directly
