I can't believe this hasn't been answered a thousand times, but I can't
seem to find the answer in the group archive.
I am parsing a string into @text (i.e. abc.def) I want to save the
part before the dot into @firstpart . For example:
@text << "a" @text << "b" @text << "c" next char is "." so @firstpart = @text
then @text << "." @text << "d", etc
The problem is, this doesn't work. @firstpart apparently is a
pointer to @text and continues to receive the characters. Freezing @firstpart doesn't work because then @text << produces a freeze error.
There doesn't appear to be a "copy" method for string, so how do I do
this?
I can't believe this hasn't been answered a thousand times, but I can't
seem to find the answer in the group archive.
I am parsing a string into @text (i.e. abc.def) I want to save the
part before the dot into @firstpart . For example:
@text << "a" @text << "b" @text << "c" next char is "." so @firstpart = @text
then @text << "." @text << "d", etc
The problem is, this doesn't work. @firstpart apparently is a
pointer to @text and continues to receive the characters. Freezing @firstpart doesn't work because then @text << produces a freeze error.
There doesn't appear to be a "copy" method for string, so how do I do
this?
Sometimes the obvious eludes us....
Bill
Your code sample doesn't run at all. Here's one that does.
text = ""
text << "a"
text << "b"
text << "c"
first_part = text.dup
text << "."
text << "d"
WoodHacker wrote:
> I can't believe this hasn't been answered a thousand times, but I can't
> seem to find the answer in the group archive.
>
> I am parsing a string into @text (i.e. abc.def) I want to save the
> part before the dot into @firstpart . For example:
>
> @text << "a"
> @text << "b"
> @text << "c" next char is "." so @firstpart = @text
> then @text << "."
> @text << "d", etc
>
> The problem is, this doesn't work. @firstpart apparently is a
> pointer to @text and continues to receive the characters. Freezing
> @firstpart doesn't work because then @text << produces a freeze error.
> There doesn't appear to be a "copy" method for string, so how do I do
> this?
>
> Sometimes the obvious eludes us....
>
> Bill
Your code sample doesn't run at all. Here's one that does.
text = ""
text << "a"
text << "b"
text << "c"
first_part = text.dup
text << "."
text << "d"