Bug in $.?

ruby-talk
1

cat t

def out; print "#$. "; end # print $. plus a space
out
$. = 0
out
DATA.each { out }
puts
__END__
1
2
3
4

ruby t

7 0 8 9 10 11

This should, probably even without the $.=0 statement, print:
7 0 1 2 3 4

Am I wrong?

···

--
Wybo

2

Wybo Dekker wrote:

>cat t
def out; print "#$. "; end # print $. plus a space
out
$. = 0
out
DATA.each { out }
puts
__END__
1
2
3
4
>ruby t
7 0 8 9 10 11

This should, probably even without the $.=0 statement, print:
7 0 1 2 3 4

Am I wrong?

What looks like is happening (with no opinion as to it's correctness):

* DATA.lineno is 7 (6 lines of code + the __END__ line), so the initial
value's reasonable

* when you assign to $. it's affecting $<.lineno (which makes sense)

* however when you do "$. = 0", $< is the handle ARGF, not DATA

* after the code was read, $< got changed to the ARGF handle but $.
wasn't reset

* you then start reading from DATA, so $. gets associated with it again
and $. is back to 7

···

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