Array's methods and operators in Ruby

ruby-talk
1

What's the method/operator between the two arrays for purpose like,
arr1=[1,2,3,4,5,6,7,8,9,10]
arr2=[2,5,9]
#code to remove the item of arr2 from arr1.
p arr1

#=>[1,3,4,6,7,8,10]

another is,
arr3=[a,b,c,d,e,f,g,h,i,j,k,l,m,n,o]
arr4=[a,i,n]
#code to remove the item of arr4 from arr3.
p arr3

#=>[b,c,d,e,f,g,h,j,k,l,m,o]

···

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2

Selvag Ruby wrote in post #1134352:

What's the method/operator between the two arrays for purpose like,
arr1=[1,2,3,4,5,6,7,8,9,10]
arr2=[2,5,9]
#code to remove the item of arr2 from arr1.
p arr1

#=>[1,3,4,6,7,8,10]

another is,
arr3=[a,b,c,d,e,f,g,h,i,j,k,l,m,n,o]
arr4=[a,i,n]
#code to remove the item of arr4 from arr3.
p arr3

#=>[b,c,d,e,f,g,h,j,k,l,m,o]

p arr1 - arr2

···

--
Posted via http://www.ruby-forum.com/\.

3

say method to do that.

···

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4

The method is subtracting one array from another. I know it seems too
simple, but that's what Ruby's like. Lots of amazingly simple methods
which would be complex in another language :slight_smile:

arr1 - arr2

···

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