a = ["A","A","A","A","A", "A","A","A","A","A"]
a[3...7] = "B"
QUESTION:
after code executes a = ["A", "A", "A", "B", "A", "A", "A"]
what should I do to make a = ["A", "A", "A", "B", "B", "B", "B", "A",
"A", "A"]
--
Posted via http://www.ruby-forum.com/.
Just
a[3...7] = ['B','B','B','B'].
Works at least in 1.9.2.
2011/3/18 Ruby Fan <sweensonti@garrifulio.mailexpire.com>
a = ["A","A","A","A","A", "A","A","A","A","A"]
a[3...7] = "B"QUESTION:
after code executes a = ["A", "A", "A", "B", "A", "A", "A"]
what should I do to make a = ["A", "A", "A", "B", "B", "B", "B", "A",
"A", "A"]--
Posted via http://www.ruby-forum.com/\.
I understand that 
But I need some universal way to change values of arrays with 10+
elements
--
Posted via http://www.ruby-forum.com/.
Found way:
b = []
a[3...7].size.times do b.push("B") end
a[3...7] = b
is there anything simplier?
--
Posted via http://www.ruby-forum.com/.
You can use the fill method in the Array class
e.g from the Ruby docs
a.fill("z", 2, 2) #=> ["x", "x", "z", "z"]
a.fill("y", 0..1) #=> ["y", "y", "z", "z"]
Please refer to the Ruby docs for other ways to use the fill method
http://railsapi.com/doc/ruby-v1.9.2/classes/Array.html#M000097
--
Posted via http://www.ruby-forum.com/.
Not necessarily any simpler, but perhaps a bit more efficient:
3...7.each { |i| a[i] = "B" }
Wrap it up into a nice method:
class Array
def replace_range_with(range, replacement)
range.each { |i| self[i] = replacement }
self
end
end
a = ["A", "A", "A", "A", "A"]
a.replace_range_with(2...4, "B") #=> ["A", "A", "B", "B", "A"]
-Jeremy
On 3/18/2011 10:22, Ruby Fan wrote:
Found way:
b =
a[3...7].size.times do b.push("B") end
a[3...7] = bis there anything simplier?
in some cases, specifying the starting and the length may be also handy, eg,
a=["A"]*10
#=> ["A", "A", "A", "A", "A", "A", "A", "A", "A", "A"]
a[3,4]=["B"]*4
#=> ["B", "B", "B", "B"]
a
#=> ["A", "A", "A", "B", "B", "B", "B", "A", "A", "A"]
and ff jeremy's wrapping,
class Array
def replacex start,length, item
self[start,length]=[item]*length
end
end
#=> nil
a=["A"]*10
#=> ["A", "A", "A", "A", "A", "A", "A", "A", "A", "A"]
a.replacex 3, 4,"B"
#=> ["B", "B", "B", "B"]
a
#=> ["A", "A", "A", "B", "B", "B", "B", "A", "A", "A"]
best regards -botp
On Fri, Mar 18, 2011 at 11:31 PM, Jeremy Bopp <jeremy@bopp.net> wrote:
On 3/18/2011 10:22, Ruby Fan wrote:
Found way:
b =
a[3...7].size.times do b.push("B") end
a[3...7] = b3...7.each { |i| a[i] = "B" }
class Array
def replace_range_with(range, replacement)
range.each { |i| self[i] = replacement }
self
end
end
a = ["A", "A", "A", "A", "A"]
a.replace_range_with(2...4, "B") #=> ["A", "A", "B", "B", "A"]