Gentelmans: …(There are any woman around there ?)
I would love to be able to do:
a=(1…10)
With this code, ‘a’ becomes a single Range. Try: a = *1…10.
a.each {| x , y| p x }
1
3
5
7
9
You’ll have to redefine each() to yield two elements instead of one in order
to get this behavior. Or you could just use step:
0.step(a.length,2){ |i| p a[i] }
(IMHO … following the principle of the least surprise…may it
should be a native behavior .)
You mean Ruby should automatically yield as many parameters as the block
expects? You’ll have to talk to Matz about that one. 
Regards,
Dan
Gentelmans: …(There are any woman around there ?)
I would love to be able to do:
a=(1…10)
With this code, ‘a’ becomes a single Range. Try: a = *1…10.
a.each {| x , y| p x }
1
3
5
7
9
You’ll have to redefine each() to yield two elements instead of one in order
to get this behavior. Or you could just use step:
0.step(a.length,2){ |i| p a[i] }
(IMHO … following the principle of the least surprise…may it
should be a native behavior .)
You mean Ruby should automatically yield as many parameters as the block
expects? You’ll have to talk to Matz about that one.
Something like that?
[gus@comp ex]$ cat eachn.rb
module Enumerable
def each_n(&b)
i =
n = b.arity
n = -n if n <= 1
k = n
self.each { |x|
i << x
k -= 1
if k <= 0
b.call(*i)
i =
k = n
end
}
unless i.empty?
i += Array.new(n - i.length)
b.call(*i) unless i.empty?
end
end
end
if FILE == $0
(0…10).each_n { |x| puts “x %s” % x.inspect }
(0…10).each_n { |x, y| puts “x %s y %s” % [x.inspect, y.inspect] }
(0…10).each_n { |x, y, z| puts “x %s y %s z %s” % [x.inspect,
y.inspect, z.inspect] }
.each_n { |x, y| puts “Huh?” }
end
[gus@comp ex]$ ruby eachn.rb
x 0
x 1
x 2
x 3
x 4
x 5
x 6
x 7
x 8
x 9
x 10
x 0 y 1
x 2 y 3
x 4 y 5
x 6 y 7
x 8 y 9
x 10 y nil
x 0 y 1 z 2
x 3 y 4 z 5
x 6 y 7 z 8
x 9 y 10 z nil
Guillaume.
···
On Tue, 2003-07-08 at 15:00, Berger, Daniel wrote:
Regards,
Dan