About lambda and its binding

ruby-talk
1

is there a way to specify the binding of a proc created through lambda?

eg:

$ cat test.rb
class A
   attr_reader :foo
   def initialize
     @foo = lambda { do_that_thing }
   end
end

class B
   def do_that_thing
     puts "yeah, do it!"
   end

   def initialize
     a = A.new
     a.foo.call
   end
end

B.new

$ ruby test.rb
test.rb:4:in `initialize': undefined local variable or method `do_that_thing' for #<A:0x127f28 @foo=#<Proc:0x00128608@test.rb:4>> (NameError)
  from test.rb:15:in `call'
  from test.rb:15:in `initialize'
  from test.rb:19:in `new'
  from test.rb:19

So... is there a way to call the lambda defined in A with the binding of B?
thanks a lot for any hint...

···

--
Rolando Abarca M.

2

Rolando Abarca wrote:

So... is there a way to call the lambda defined in A with the binding
of B?
thanks a lot for any hint...

   def initialize
     a = A.new
     instance_eval(&a.foo)
   end

···

--
Posted via http://www.ruby-forum.com/\.

3

Rolando Abarca <funkaster@gmail.com> writes:

is there a way to specify the binding of a proc created through lambda?

eg:

$ cat test.rb
class A
   attr_reader :foo
   def initialize
     @foo = lambda { do_that_thing }
   end
end

class B
   def do_that_thing
     puts "yeah, do it!"
   end

   def initialize
     a = A.new
     a.foo.call
   end
end

B.new

So... is there a way to call the lambda defined in A with the binding
of B?
thanks a lot for any hint...

Can you provide more context regarding what you're trying to
accomplish? Or are you simply wanting to learn more about Ruby's
semantics?

For example, parameterizing the lambda may do what you want more
simply:

class A
  attr_reader :foo
  def initialize
    @foo = lambda {|x| x.do_that_thing }
  end
end

class B
  def do_that_thing
    puts "yeah, do it!"
  end

  def initialize
    A.new.foo.call(self)
  end
end

B.new

4

duh... I totally forgot about instance_eval :slight_smile:
thanks!!

···

On 16-10-2008, at 22:15, Mike Gold wrote:

Rolando Abarca wrote:

So... is there a way to call the lambda defined in A with the binding
of B?
thanks a lot for any hint...

  def initialize
    a = A.new
    instance_eval(&a.foo)
  end

--
Rolando Abarca M.