Jean_G
(Jean G.)
1
Hello,
This works fine for me:
class Horse
def name
@name
end
def nameset(v1,v2)
@name = v1 + v2.to_s
end
end
xx=Horse.new
xx.nameset("hello ",1)
p xx.name
But if I changed the method name, it won't work.
class Horse
def name
@name
end
def name=(v1,v2)
@name = v1 + v2.to_s
end
end
xx=Horse.new
xx.name=("hello ",1)
p xx.name
the error says:
syntax error, unexpected ',', expecting ')'
xx.name=("hello ",1)
^
Please help, thanks in advance.
Robert_K1
(Robert K.)
2
Methods with assignment operator are separately treated by the parser - as you just learned. You can only have 1 argument.
Btw, usually an assignment method, does just that. In your case you are concatenating two strings which is probably worth a different method name.
Kind regards
robert
···
On 12.12.2009 08:27, Ruby Newbee wrote:
Hello,
This works fine for me:
class Horse
def name
@name
end
def nameset(v1,v2)
@name = v1 + v2.to_s
end
end
xx=Horse.new
xx.nameset("hello ",1)
p xx.name
But if I changed the method name, it won't work.
class Horse
def name
@name
end
def name=(v1,v2)
@name = v1 + v2.to_s
end
end
xx=Horse.new
xx.name=("hello ",1)
p xx.name
the error says:
syntax error, unexpected ',', expecting ')'
xx.name=("hello ",1)
^
Please help, thanks in advance.
--
remember.guy do |as, often| as.you_can - without end
http://blog.rubybestpractices.com/
Ruby Newbee wrote:
Hello,
This works fine for me:
class Horse
def name
@name
end
def nameset(v1,v2)
@name = v1 + v2.to_s
end
end
xx=Horse.new
xx.nameset("hello ",1)
p xx.name
But if I changed the method name, it won't work.
class Horse
def name
@name
end
def name=(v1,v2)
@name = v1 + v2.to_s
end
end
xx=Horse.new
xx.name=("hello ",1)
p xx.name
the error says:
syntax error, unexpected ',', expecting ')'
xx.name=("hello ",1)
^
Please help, thanks in advance.
Hi,
class Foo
def bar
@bar
end
def bar= *args
@bar = args.join
end
end
x = Foo.new.bar= 1,2,3 # => [1,2,3]
x.bar # => "123"
- Rob
···
--
Posted via http://www.ruby-forum.com/\.
x = Foo.new.bar= 1,2,3 # => [1,2,3]
x.bar # => "123"
Oops. If you want that to work as-is..
x = Foo.new
x.bar= 1,2,3 # => [1,2,3]
x.bar # => "123"
- Rob
···
--
Posted via http://www.ruby-forum.com/\.