I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.
irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;
irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007
If you put a 0 in front of a number you are specifying an octal number instead of a decimal number. Octal is base 8, so there is no such thing as an octal number including a digit greater than 7:
t = Time.local 2007, 011, 011, 00, 00
Instead just use base 10:
Time.local 2007, 9, 9, 0, 0
···
On Feb 2, 2007, at 09:58, Peter Bailey wrote:
I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.
irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;
In Ruby starting an integer with a leading zero designates that it is in octal notation. The non-negative octal integers start 00, 01, ..., 07, 010, 011, .... There is no 09.
Bottom line: drop the leading zeros.
Regards, Morton
···
On Feb 2, 2007, at 12:58 PM, Peter Bailey wrote:
I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.
irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;
irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007
I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.
irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
Numeric literals starting with `0' are interpreted as octal numbers. Try
dropping the leading `0''s.
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;
irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007
That's because there is no `9' in the base-8 number system, just like there is
no `A' in the regular base-10 number system (but there is in the base-16
system a.k.a. hexadecimal).
Hth,
···
On Sat, Feb 03, 2007 at 02:58:59AM +0900, Peter Bailey wrote:
--
Jos Backus
jos at catnook.com
I need to check some file dates against the budgetary periods of our
company, to determine where those files get placed. I'm playing with the
Time.local object. I've proven that I can denote which budget period I'm
in by using the .between? method. But, I get this weird "octal digit"
error with some of my date entries.
irb(main):001:0> t = Time.local(2007,09,09,00,00)
SyntaxError: compile error
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
The problem is the leading zero. Time.local(2007, 9, 9, 0, 0) works
fine.
Number literals with a zero at the beginning are interpreted as octal
numbers. Since octal numbers only use digits 0..7, 9 is rejected (as
would be 8).
HTH,
AdSR
···
On Feb 2, 6:58 pm, Peter Bailey <pbai...@bna.com> wrote:
I don't get the error when I specify the following date. It doesn't seem
to like the month of September. (-;
irb(main):005:0> t = Time.local(2007,01,01,00,00)
=> Mon Jan 01 00:00:00 -0500 2007
On Feb 2, 6:58 pm, Peter Bailey <pbai...@bna.com> wrote:
^
(irb):1: Illegal octal digit
t = Time.local(2007,09,09,00,00)
^
The problem is the leading zero. Time.local(2007, 9, 9, 0, 0) works
fine.
Number literals with a zero at the beginning are interpreted as octal
numbers. Since octal numbers only use digits 0..7, 9 is rejected (as
would be 8).
HTH,
AdSR
You're all brilliant. Thanks. Yes, when I re-looked into my book that
was guiding me with this, I see that all of their sample don't have a
leading zero.