Hi,
i am new to ruby and i am wondering how many more ways (and what ways)
there are to do this:
seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
end
i suppose there's a one-liner that you write before you can think "ruby"
doesn't it ???
thx,
chris
--
Posted via http://www.ruby-forum.com/.
"hi, you, guys".split(",").map! { |x| x.strip }
On 11/9/06, Chris Mueller <damngoodcoffee@gmail.com> wrote:
Hi,
i am new to ruby and i am wondering how many more ways (and what ways)
there are to do this:seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
endi suppose there's a one-liner that you write before you can think "ruby"
doesn't it ???thx,
chris
--
Posted via http://www.ruby-forum.com/\.
Chris Mueller a écrit :
Hi,
i am new to ruby and i am wondering how many more ways (and what ways) there are to do this:seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
endi suppose there's a one-liner that you write before you can think "ruby" doesn't it ???
thx,
chris
Hi,
this is my version :
"hi, you, guys".split(',').map { |word| word.strip }
=> ["hi", "you", "guys"]
--
Bruno Michel
Functionally slightly different, but:
words_array = separated_words.split(/, /)
On 2006-11-09, Chris Mueller <damngoodcoffee@gmail.com> wrote:
Hi,
i am new to ruby and i am wondering how many more ways (and what ways)
there are to do this:seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
endi suppose there's a one-liner that you write before you can think "ruby"
doesn't it ???
Hi --
On Thu, 9 Nov 2006, Chris Mueller wrote:
Hi,
i am new to ruby and i am wondering how many more ways (and what ways)
there are to do this:seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
end
Here's one way:
separated_words.scan(/[^\s,]+/)
And another:
require 'csv'
CSV.parse_line(separated.words.delete(' '))
David
--
David A. Black | dblack@wobblini.net
Author of "Ruby for Rails" [1] | Ruby/Rails training & consultancy [3]
DABlog (DAB's Weblog) [2] | Co-director, Ruby Central, Inc. [4]
[1] Ruby for Rails | [3] http://www.rubypowerandlight.com
[2] http://dablog.rubypal.com | [4] http://www.rubycentral.org
My favourite cheat is....
$ irb
irb(main):001:0> %w{hi you guys}
=> ["hi", "you", "guys"]
irb(main):002:0>
Not quite as much as a cheat as you think....
People keep creating small ugly special purpose once off data
languages like xml, csv, yaml,...
Unless there is a pressing need to store in language neutral format,
for pity sake don't.
Just store your data as plain old ruby.
Simpler and more expressive.
John Carter Phone : (64)(3) 358 6639
Tait Electronics Fax : (64)(3) 359 4632
PO Box 1645 Christchurch Email : john.carter@tait.co.nz
New Zealand
On Thu, 9 Nov 2006, Chris Mueller wrote:
i suppose there's a one-liner that you write before you can think "ruby"
doesn't it ???
Chris Mueller wrote:
Hi,
i am new to ruby and i am wondering how many more ways (and what ways)
there are to do this:seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
endi suppose there's a one-liner that you write before you can think "ruby"
Chris,
Assuming that the string convention stays a comma plus a single space
between words why not add the single space in to the split string and
write
seperated_words = "hi, you, guys"
word_array = seperated_words.split(", ")
CParticle
Split recieves a regexp as an argument. So you can be as tricky as you like
with it.
"hi, you, guys".split( %r{\s*,\s*} )
=>[ "hi","you","guys"]
Your version has no side-effect on the array, so it's not exactly the
same as the original ... 
On 11/9/06, Bruno Michel <bruno@exceliance.fr> wrote:
Chris Mueller a écrit :
> Hi,
> i am new to ruby and i am wondering how many more ways (and what ways)
> there are to do this:
>
> seperated_words = "hi, you, guys"
> words_array = seperated_words.split(",")
> for i in 0 ... words_array.length
> words_array[i] = words_array[i].strip
> end
>
> i suppose there's a one-liner that you write before you can think "ruby"
> doesn't it ???
>
> thx,
>
> chrisHi,
this is my version :
"hi, you, guys".split(',').map { |word| word.strip }
=> ["hi", "you", "guys"]--
Bruno Michel
And yet another one
irb(main):002:0> "hi, you, guys".split /\s*,\s*/
=> ["hi", "you", "guys"]
irb(main):003:0> "hi, you, guys".scan /\w+/
=> ["hi", "you", "guys"]
Cheers
robert
Kero <kero@chello.single-dot.nl> wrote:
On 2006-11-09, Chris Mueller <damngoodcoffee@gmail.com> wrote:
Hi,
i am new to ruby and i am wondering how many more ways (and what
ways) there are to do this:seperated_words = "hi, you, guys"
words_array = seperated_words.split(",")
for i in 0 ... words_array.length
words_array[i] = words_array[i].strip
endi suppose there's a one-liner that you write before you can think
"ruby" doesn't it ???Functionally slightly different, but:
words_array = separated_words.split(/, /)
Charged Particle wrote:
Assuming that the string convention stays a comma plus a single space
between words why not add the single space in to the split string and
write
i forgot to mention that the comma seperated list comes from a text_area
and may not include a whitespace after each ","
thank you all for your posts, i learned quite a lot about the many roads
to rome that ruby (and regex) provides
p.s: maybe i should start another competiton 
--
Posted via http://www.ruby-forum.com/\.
good timing to you first two guys;)
thx very much. got some new ruby cells working in my brain.
i tried same thing as ".map" with "array.each" before, but this does
only apply on a copy i suppose...
and of course the regexp way is ... groovy!
--
Posted via http://www.ruby-forum.com/.
use map! instead
On 11/9/06, Chris Mueller <damngoodcoffee@gmail.com> wrote:
good timing to you first two guys;)
thx very much. got some new ruby cells working in my brain.
i tried same thing as ".map" with "array.each" before, but this does
only apply on a copy i suppose...and of course the regexp way is ... groovy!
--
Posted via http://www.ruby-forum.com/\.
use map! instead
nope,
try to understand the difference between split(regexp), map and map!
than decide for yourself
Look at this for example
"he, nice, guys".split(',').map!{|x| x.strip}
why would you use map! ?
try to put the above expression into a context
e.g.
x = ...
Hint: using map! on unreferenced objects is quite useless.
What about
x= "he, nice".split(",")
x.map!{|x|x.strip}
try
x.map!{|x|x.strip!}
would you like to use this?
If you want to walk do not learn to drive
Cheers
Robert
On 11/9/06, spooq <spoooq@gmail.com> wrote:
On 11/9/06, Chris Mueller <damngoodcoffee@gmail.com> wrote:
> good timing to you first two guys;)
>
> thx very much. got some new ruby cells working in my brain.
>
> i tried same thing as ".map" with "array.each" before, but this does
> only apply on a copy i suppose...
>
> and of course the regexp way is ... groovy!
>
> --
> Posted via http://www.ruby-forum.com/\.
>
--
The reasonable man adapts himself to the world; the unreasonable one
persists in trying to adapt the world to himself. Therefore all progress
depends on the unreasonable man.
- George Bernard Shaw
>
> use map! insteadnope,
try to understand the difference between split(regexp), map and map!
than decide for yourself
Look at this for example"he, nice, guys".split(',').map!{|x| x.strip}
why would you use map! ?
try to put the above expression into a context
e.g.
x = ...Hint: using map! on unreferenced objects is quite useless.
Robert, I don't really understand what you mean. My understanding is that
these do different things. Can I walk through this in pseudo pseudo code to
increase my understanding;)
split the string into an unref'ed array
take the unreffed array and strip each element in place, creating a new
string at each element in the original array
Total Arrays created 2
How does this not differ from
"he, nice, guys".split(',').map{|x| x.strip}
Where, my understanding would be
split the string into an unref'ed array
take the unref'ed array, and create a new array from the result of each
element stripped.
ie. a new string object for each element put into a new array
Total Arrays created 3
What about
x= "he, nice".split(",")
x.map!{|x|x.strip}
split the string and assign it to an array
modify each element in place and strip the result. (creating a new string
for each element)
try
x.map!{|x|x.strip!}
would you like to use this?
Nasty... Turns the first element (with no whitespace) into nil
Have I understood the difference/similarities here or have I missed the
ball?
On 11/9/06, Robert Dober <robert.dober@gmail.com> wrote:
On 11/9/06, spooq <spoooq@gmail.com> wrote:
you are absolutely correct, my mind is rotting from weeks of sitting
at my desk twiddling my thumbs with no work to do.
On 11/9/06, Robert Dober <robert.dober@gmail.com> wrote:
On 11/9/06, spooq <spoooq@gmail.com> wrote:
>
> use map! insteadnope,
try to understand the difference between split(regexp), map and map!
than decide for yourself
Look at this for example"he, nice, guys".split(',').map!{|x| x.strip}
why would you use map! ?
try to put the above expression into a context
e.g.
x = ...Hint: using map! on unreferenced objects is quite useless.
What about
x= "he, nice".split(",")
x.map!{|x|x.strip}try
x.map!{|x|x.strip!}
would you like to use this?If you want to walk do not learn to drive
Cheers
RobertOn 11/9/06, Chris Mueller <damngoodcoffee@gmail.com> wrote:
> > good timing to you first two guys;)
> >
> > thx very much. got some new ruby cells working in my brain.
> >
> > i tried same thing as ".map" with "array.each" before, but this does
> > only apply on a copy i suppose...
> >
> > and of course the regexp way is ... groovy!
> >
> > --
> > Posted via http://www.ruby-forum.com/\.
> >
>--
The reasonable man adapts himself to the world; the unreasonable one
persists in trying to adapt the world to himself. Therefore all progress
depends on the unreasonable man.- George Bernard Shaw
>
> >
> > use map! instead
>
> nope,
> try to understand the difference between split(regexp), map and map!
> than decide for yourself
> Look at this for example
>
> "he, nice, guys".split(',').map!{|x| x.strip}
"he, nice, guys".split(",") ===> tmp1 <-- ["he", " nice", " guys" ]
tmp1.map!{|x| x.strip} ===> tmp2 <-- ["he", "nice", "guys"] ** and
modifies the object referenced by tmp1 in place ***
why would you use map! ?
> try to put the above expression into a context
> e.g.
> x = ...
>
> Hint: using map! on unreferenced objects is quite useless.
The idea was to work on the differences between xxx and xxx!
Robert, I don't really understand what you mean. My understanding is that
these do different things. Can I walk through this in pseudo pseudo code
to
increase my understanding;)
Excellent idea.
split the string into an unref'ed array
take the unreffed array and strip each element in place, creating a new
string at each element in the original array
which will get lost, the only thing you use is the result of the
expression, s
Total Arrays created 2
I have no idea
How does this not differ from
"he, nice, guys".split(',').map{|x| x.strip}
"he, nice, guys".split(",") ===> tmp1 <-- ["he", " nice", " guys" ]
tmp1.map!{|x| x.strip} ===> tmp2 <-- ["he", "nice", "guys"] ***
without modifiying tmp1 inplace ***
Performance is not an issue, but I guess it is important to understand why
one would apply map! (ignoring the existance of map would not be a good
reason)
Where, my understanding would be
split the string into an unref'ed array
take the unref'ed array, and create a new array from the result of each
element stripped.
ie. a new string object for each element put into a new array
exactly (this is done too above, it would not work else)
Total Arrays created 3
Again I have no idea
What about
> x= "he, nice".split(",")
> x.map!{|x|x.strip}split the string and assign it to an array
modify each element in place and strip the result. (creating a new string
for each element)try
> x.map!{|x|x.strip!}
> would you like to use this?Nasty... Turns the first element (with no whitespace) into nil
No for the same reason as above why use x.strip! modifiying x when x will
be discarded immediately? I thaught this would be the ice breaker example
Have I understood the difference/similarities here or have I missed the
ball?
Baseball?
BTW Sometimes I get caught in the urge to explain, forgetting that
experience has shown to me that I am quite a bad teacher
Cheers
Robert
On 11/9/06, Daniel N <has.sox@gmail.com> wrote:
On 11/9/06, Robert Dober <robert.dober@gmail.com> wrote:
> On 11/9/06, spooq <spoooq@gmail.com> wrote:
--
The reasonable man adapts himself to the world; the unreasonable one
persists in trying to adapt the world to himself. Therefore all progress
depends on the unreasonable man.
- George Bernard Shaw