But when might the 1st way (using the unary operator) be preferred to
the more explicit 2nd way?
Oops. Scratch that last question.
Hi --
a = [1,2,3]
x(a) # [[1,2,3,]]
x(*a) # [1,2,3]x(*a) # [1,2,3]
x(a.to_a) # also [1,2,3]But when might the 1st way (using the unary operator) be preferred to
the more explicit 2nd way?
I did leave off the to_a, though array.to_a is a no-op so it shouldn't
matter.
More to the point: what version of Ruby are you using? Here's the
output with 1.8.3:
$ cat args2.rb
def x(*args)
p args
end
a = [1,2,3]
x(a.to_a)
x(*a)
$ ruby -v args2.rb ruby 1.8.3 (2005-09-21) [powerpc-darwin8.3.0]
[[1, 2, 3]]
[1, 2, 3]
David
···
On Fri, 2 Dec 2005, Brian Buckley wrote:
--
David A. Black
dblack@wobblini.net
Hi --
···
On Fri, 2 Dec 2005, Daniel Schierbeck wrote:
David A. Black wrote:
As Gary says it's actually to_a, not to_ary
#to_ary is called first; if it doesn't exist #to_a will be called.
Whoops -- I got a false negative on a (flawed) little test I ran.
David
--
David A. Black
dblack@wobblini.net
More to the point: what version of Ruby are you using? Here's the
output with 1.8.3:
I am an older version (1.8.2) but I am getting the same result as you.
I didn't realize you'd intentionally omitted to noop to_a. That and
with Ross's explanation, now I get it.