# Regexp
**URL:** https://rubytalk.org/t/regexp/53391
**Category:** ruby-talk
**Created:** [14 May 2009 11:01 UTC](https://rubytalk.org/t/regexp/53391 "2009-05-14T11:01:57Z")
**Posts on this page:** 5
**Page:** 1
### Author:  [@Mikael\_Bjorkegren](https://rubytalk.org/u/Mikael_Bjorkegren)
#### Post date: [14 May 2009 11:01 UTC](https://rubytalk.org/t/regexp/53391/1 "2009-05-14T11:01:57Z")
Hello!
Anyone who can help me with this. If i have a string and want to take
out a sub string of that by regexp.
1. string = "Today is it monday after work. blah blah."
or
2. string2 = "monday morning. Nice day today."
And i would like to get a certain line with the word monday in it.
Like results below.
1. result = "Today is it monday after work"
2. result2 = "monday morning"
Thanks
Svea
> **···**
>
> --
> Posted via [http://www.ruby-forum.com/](http://www.ruby-forum.com/).
---
### Author:  [@Clemens\_Wyss](https://rubytalk.org/u/Clemens_Wyss)
#### Post date: [14 May 2009 11:48 UTC](https://rubytalk.org/t/regexp/53391/2 "2009-05-14T11:48:31Z")
simple, but for sure not perfect:
/(?:.\*?\.)\*(.\*?monday.\*?)\./.match(\)[1]
e.g.:
/(?:.\*?\.)\*(.\*?monday.\*?)\./.match('asdasd . asdas dasd .it is monday
morning. hello world')[1]
=\> "it is monday morning"
Regards
Clemens
Mikael Björkegren wrote:
> **···**
>
> > Hello!
> >
> > Anyone who can help me with this. If i have a string and want to take
> > out a sub string of that by regexp.
> >
> > 1. string = "Today is it monday after work. blah blah."
> > or
> > 2. string2 = "monday morning. Nice day today."
> >
> > And i would like to get a certain line with the word monday in it.
> > Like results below.
> >
> > 1. result = "Today is it monday after work"
> > 2. result2 = "monday morning"
> >
> > Thanks
> > Svea
>
> --
> Posted via [http://www.ruby-forum.com/\](http://www.ruby-forum.com/%5C).
---
### Author:  [@Mark\_Thomas](https://rubytalk.org/u/Mark_Thomas)
#### Post date: [14 May 2009 11:50 UTC](https://rubytalk.org/t/regexp/53391/3 "2009-05-14T11:50:15Z")
So you want the sentence, not including the period? What if there is a
preceding sentence?
Try
puts string[/[^.]\*[Mm]onday[^.]\*/]
-- Mark.
> **···**
>
> On May 14, 7:01 am, Mikael Björkegren \ wrote:
>
> > Hello!
> >
> > Anyone who can help me with this. If i have a string and want to take
> > out a sub string of that by regexp.
> >
> > 1. string = "Today is it monday after work. blah blah."
> > or
> > 2. string2 = "monday morning. Nice day today."
> >
> > And i would like to get a certain line with the word monday in it.
> > Like results below.
> >
> > 1. result = "Today is it monday after work"
> > 2. result2 = "monday morning"
---
### Author:  [@Mikael\_Bjorkegren](https://rubytalk.org/u/Mikael_Bjorkegren)
#### Post date: [14 May 2009 11:58 UTC](https://rubytalk.org/t/regexp/53391/4 "2009-05-14T11:58:13Z")
Thanks for the fast reply.
Works nice for stripping the last part but not the first.
I get the lines before also.
/(?:.\*?\.)\*(.\*?monday.\*?)\./.match('asdasd . asdas dasd .it is monday
morning. hello world')
=\> asdasd . asdas dasd .it is monday morning.
> **···**
>
> > e.g.:
> > /(?:.\*?\.)\*(.\*?monday.\*?)\./.match('asdasd . asdas dasd .it is monday
> > morning. hello world')[1]
> > =\> "it is monday morning"
>
> --
> Posted via [http://www.ruby-forum.com/\](http://www.ruby-forum.com/%5C).
---
### Author:  [@Mikael\_Bjorkegren](https://rubytalk.org/u/Mikael_Bjorkegren)
#### Post date: [14 May 2009 12:02 UTC](https://rubytalk.org/t/regexp/53391/5 "2009-05-14T12:02:35Z")
Never mind i forgott [1]
Thanks again
> **···**
>
> > /(?:.\*?\.)\*(.\*?monday.\*?)\./.match('asdasd . asdas dasd .it is monday
> > morning. hello world')
> > =\> asdasd . asdas dasd .it is monday morning.
> >
> > > e.g.:
> > > /(?:.\*?\.)\*(.\*?monday.\*?)\./.match('asdasd . asdas dasd .it is monday
> > > morning. hello world')[1]
> > > =\> "it is monday morning"
>
> --
> Posted via [http://www.ruby-forum.com/\](http://www.ruby-forum.com/%5C).