Proc return statement

ruby-talk
1

@@mappings.each{ |hsh|
        begin
          if( hsh['type'] == c['type'] ) then
            eval( "comp=#{hsh['template']}" )
            hsh.each_key{ |key|
              m = proc { @@ignore.each{ |i| return true if( key == i )

}

}.call

Should be: proc{break true if... }.call
'return' returns from the encompassing method. 'break' return from the
proc.

             puts m;
            }
            has_mapping = true;
          end
        rescue; raise "Unable to evaluate passed in expression:
#{hsh['template']}"; end
        break if( has_mapping ); }

It is at the line: m = proc { @@ignore.each{ |i| return true if(

key

···

== i ) } }.call
that I am having the problem. I want "m" to be true, but instead it
leaves the calling function.

I have modified the line to be:

m = nil;
proc { @@ignore.each{ |i| m=true if( key == i ) } }.call

but I was just wondering if I could return a value w/o having to leave

the outer function.

Zach

2

Mehr, Assaph (Assaph) wrote:

@@mappings.each{ |hsh|
       begin
         if( hsh['type'] == c['type'] ) then
           eval( "comp=#{hsh['template']}" )
           hsh.each_key{ |key|
             m = proc { @@ignore.each{ |i| return true if( key == i )
   

}

}.call
   
Should be: proc{break true if... }.call
'return' returns from the encompassing method. 'break' return from the
proc.

Thanks Assaph.

Zach