I had an escape character match in the regexp:
/ [^`] \[(.+?)\] /x
That was messing it up (Don't really know why) but I just "zeroed"
it:
/ (?=[^`]) \[(.+?)\] /x
And that did the trick.
Thats because [^`] will match 'a single character that is not `'.
When you did the zero-width lookahead, you made into 'possibly a
character, so long as it's not ` '.
Hope this makes sense 
I may be reading this wrong, but I think that with the zero-width
lookahead, it is now ensuring that the first character of the match is
not a backtick. Which, since it's always going to be a square bracket,
makes the lookahead superfluous.
If you need escaping, try:
/(?: # escape sequence match
^ | [^`] # alternate: match either "start of line" or a non-backtick.
)
( # non-greedy [foo] match
\[.*?\]
)/
... then use $1. This one won't match any paired square brackets
immediately preceded by a backtick.
cheers,
Mark
On Tue, 18 Jan 2005 07:31:06 +0900, Assaph Mehr <assaph@gmail.com> wrote:
> I had an escape character match in the regexp:
>
> / [^`] \[(.+?)\] /x
>
> That was messing it up (Don't really know why) but I just "zeroed"
it:
>
> / (?=[^`]) \[(.+?)\] /x
>
> And that did the trick.Thats because [^`] will match 'a single character that is not `'.
When you did the zero-width lookahead, you made into 'possibly a
character, so long as it's not ` '.