Not sure how index function works with regex
a = [“this”,“is”,“his”,“book”]
puts a.index(“is”) # 1
puts a.index(/is/) # nil (Why?)
Any ideas?
Thanks,
–Shanko
Not sure how index function works with regex
a = [“this”,“is”,“his”,“book”]
puts a.index(“is”) # 1
puts a.index(/is/) # nil (Why?)
Any ideas?
Thanks,
–Shanko
Not sure how index function works with regex
ruby call #==, try
a = ["this","is","his","book", /is/]
puts a.index(/is/)
Guy Decoux
Hi,
In message “index regex question” on 02/06/27, “Shashank Date” ADATE@kc.rr.com writes:
Not sure how index function works with regex
Array#index uses “==” to compare, so the answer is “no”.
matz.
Thanks, matz.
I have worked around the problem using Array#each_with_index.
n = nil
a = [“this”,“is”,“his”,“book”]
a.each_with_index {|r,i|
n = i if (r =~ /^is$/)
break if n
}
And to get the effect of Array # rindex just comment out the break
statement.
Any other suggestions are highly welcome.
– Shanko
“Yukihiro Matsumoto” matz@ruby-lang.org wrote in message
news:1025154592.403173.3285.nullmailer@picachu.netlab.jp…
Hi,
In message “index regex question” > on 02/06/27, “Shashank Date” ADATE@kc.rr.com writes:
Not sure how index function works with regex
Array#index uses “==” to compare, so the answer is “no”.
matz.