How do i turn an object into a binding?

ruby-talk
1

I have code such as this:

foo.bar
foo.baz(1)
foo.bagaloo('didoo')

instead i want to write it like this:

with (foo) do
   bar
   baz(1)
   bagaloo('didoo')
end

how?

···

_____________________
  Bret Pettichord
  www.pettichord.com

2

Bret Pettichord wrote:

how?

foo.instance_eval do
  bar
  baz(1)
  bagaloo('didoo')
end

···

--
Florian Frank

3

Note that this won't work if you try to use assignment, because that
will be interpreted as a local variable. Better:

  module Kernel
    def with(obj)
      yield self if block_given?
    end
  end

  with longfooname do |f|
    f.bar
    f.baz(1)
    f.bagaloo('didoo')
  end

-austin

···

On Sat, 29 Jan 2005 07:29:59 +0900, Florian Frank <flori@nixe.ping.de> wrote:

Bret Pettichord wrote:

> how?

foo.instance_eval do
  bar
  baz(1)
  bagaloo('didoo')
end

--
Austin Ziegler * halostatue@gmail.com
               * Alternate: austin@halostatue.ca

4

Austin Ziegler wrote:

Note that this won't work if you try to use assignment, because that
will be interpreted as a local variable.

True. In this case 'self' could be used:

foo.instance_eval do
  self.quux = true
end

If assignment methods haven't yet been defined in a class definition, the same problem occurs.

Better:

module Kernel
   def with(obj)
     yield self if block_given?
   end
end

with longfooname do |f|
   f.bar
   f.baz(1)
   f.bagaloo('didoo')
end

-austin

Well, than you could do f = longfooname at the beginning as well. :wink:

···

--
Florian Frank