++ Help

ruby-talk
1

I am learning Ruby.
This is my problem.
d=0
if some == 1..90
a=1
b=4
d++
end

I get a syntax error.

syntax error, unexpected kEND

if I take the d++ then it is ok.

how should I use the ++ or +=?

Thanks

···

--
Posted via http://www.ruby-forum.com/.

2

Ruby does not have pre or post-increment/decrement operators.
d++ should be: d += 1

Also, this probably doesn't do what you want:
"if some == 1..90"
I suspect you want to say: if (1..90).include?(something)

···

On 9/9/07, Luis Enrique <mail41t-now@yahoo.com> wrote:

I am learning Ruby.
This is my problem.
d=0
if some == 1..90
a=1
b=4
d++
end

I get a syntax error.

syntax error, unexpected kEND

if I take the d++ then it is ok.

how should I use the ++ or +=?

3

Hi,

> I am learning Ruby.
> This is my problem.
> d=0
> if some == 1..90
> a=1
> b=4
> d++
> end
>
> syntax error, unexpected kEND
>
> if I take the d++ then it is ok.

Ruby does not have pre or post-increment/decrement operators.
d++ should be: d += 1

Also, this probably doesn't do what you want:
"if some == 1..90"
I suspect you want to say: if (1..90).include?(something)

Do yourself a favour and indent your code.

  d = 0
  if (1..90).include? d then
    a = 1
    b = 4
    d += 1
  end

There further is the === operator that is used by the case
statement. So you may say:

  d = 0
  if (1..90) === d then
    a, b = 1, 4
    d += 1
  end

or even

  d = 0
  case d
    when 1..90 then
      a, b = 1, 4
      d += 1
  end

Bertram

···

Am Montag, 10. Sep 2007, 12:57:36 +0900 schrieb Wilson Bilkovich:

On 9/9/07, Luis Enrique <mail41t-now@yahoo.com> wrote:

--
Bertram Scharpf
Stuttgart, Deutschland/Germany
http://www.bertram-scharpf.de

4

  d = 0
  if (1..90).include? d then
    a = 1
    b = 4
    d += 1
  end

Interesting, I didn't know ruby had a "then" keyword. I've only seen it
when I'm doing VB stuff.

~Jeremy

···

--
Posted via http://www.ruby-forum.com/.

5

I mostly only use "then" when it's a one liner, and in that case, you
can replace it with a colon.

if x.nil? : puts y end

etc.

···

On 9/10/07, Jeremy Woertink <jeremywoertink@gmail.com> wrote:

> d = 0
> if (1..90).include? d then
> a = 1
> b = 4
> d += 1
> end

Interesting, I didn't know ruby had a "then" keyword. I've only seen it
when I'm doing VB stuff.

~Jeremy
--
Posted via http://www.ruby-forum.com/.

6

> d = 0
> if (1..90).include? d then
> a = 1
> b = 4
> d += 1
> end

Interesting, I didn't know ruby had a "then" keyword. I've only seen it
when I'm doing VB stuff.

~Jeremy
--
Posted via http://www.ruby-forum.com/.

···

On 9/10/07, Jeremy Woertink <jeremywoertink@gmail.com> wrote: