-------- Original-Nachricht --------
Datum: Sun, 2 Dec 2007 17:44:56 +0900
Von: "Mike Mr." <saltydog4791@gmail.com>
An: ruby-talk@ruby-lang.org
Betreff: file renaming/parsing help
First of all let me say that I am an absolute newb when it comes to
rails. I am simply trying to work on an existing script that was
written by someone else.
I need to take a filename that will always have a similar name and turn
it into an rfc2822 compliant line for an xml file. Here is what I have
so far but I am absolutely lost as you can see. sad
The filenames will always be the same, e.g. November 15,2007.mp3 or
September 7,2008.mp3, etc. One thing I am concerned about is the day
since sometimes it will be a single digit and sometimes a double digit,
although I am sure their is a way around that too.
I would love if someone could shed some light on this for me. I might
even learn something in the process. smile
#The goal is turn "November 15,2007.mp3" into "Wed, 15 Nov 2007 19:00:00
GMT"
#
#So far the output below gives me Wed, Nov15
filename = "November 15, 2007.mp3"
puts "Wed, " + ( filename[0,3]) + ( filename[-12,2])
--
Posted via http://www.ruby-forum.com/\.
Dear Mike,
here's some code using regexps .. that avoids knowing
the exact indices where your one-digit or two-digit day information is.
To get the day of week, you can use the time class of Ruby.
(class Time - RDoc Documentation)
Best regards,
Axel
···
------------------------------------------------------------
require "time"
mp_files=["November 15, 2007.mp3"]
result=
month=["January","February","March","April","May","June","July","August","September","October","November","December"]
year=/(1|2)[0-9]{3}/ # year must start in 1 or in 2 and have 4 digits
day=/[0-9]{1,2}/
file_month=''
file_year=''
file_day=''
mp_files.each{|file_name|
file_name.sub!(/\.[^\.]*$/,'') # chop off endings
month.each{|m| if file_name.index(m)!=nil; file_month=m; break; end}
if file_month==''
raise "No month given for file : " + file_name
end
ref_year=year.match(file_name)
if ref_year!=nil
file_year=ref_year[0]
else
raise "No year given for file : " + file_name
end
file_name.sub!(ref_year[0],'') # remove year, so that doesn't interfere with search for file_name's day
ref_day=day.match(file_name)
if ref_day!=nil
file_day=ref_day[0]
else
raise "No day given for file : " + file_name
end
# get day of week
dow=Time.parse([file_month,file_day,file_year].join(' ')).wday
result<<Time.parse([file_month,file_day,file_year].join(' ')).to_s
}
p 'result'
p result
--
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