External to Internal

ruby-talk
1

Hi,

I want to convert data supplied by a file into their corresponding internal values.

I have an external file with data that are in the form "variable name", tab, followed by their value. The 'value 'can be a single number, an array of numbers, or a matrix of numbers, For example, the file might look like this:
a 2.4
b 1,0, 3.0, 5.0
c 5, 6, 11
d [1, 2], [5, 6], [45,55]

I can get a, b, and c to convert to single values and arrays, thanks to this forum, but I cannot figure out a way to convert d into an array of arrays. Does anyone have any suggestions?

Ideally I would like to match the variable name in the file to the corresponding and same name in the program. Any ideas how to do that?

Thanks

Pete Versteegen

2

Peter Versteegen wrote:

Hi,

I want to convert data supplied by a file into their corresponding internal values.

I have an external file with data that are in the form "variable name", tab, followed by their value. The 'value 'can be a single number, an array of numbers, or a matrix of numbers, For example, the file might look like this:
a 2.4
b 1,0, 3.0, 5.0
c 5, 6, 11
d [1, 2], [5, 6], [45,55]

I can get a, b, and c to convert to single values and arrays, thanks to this forum, but I cannot figure out a way to convert d into an array of arrays. Does anyone have any suggestions?

Just insert an = :

a = 2.4
b = 1,0, 3.0, 5.0
c = 5, 6, 11
d = [1, 2], [5, 6], [45,55]

p a, b, c, d

__END__

Output:

2.4
[1, 0, 3.0, 5.0]
[5, 6, 11]
[[1, 2], [5, 6], [45, 55]]

Ideally I would like to match the variable name in the file to the corresponding and same name in the program. Any ideas how to do that?

input = <<END
a = 2.4
b = 1,0, 3.0, 5.0
c = 5, 6, 11
d = [1, 2], [5, 6], [45,55]
END

a = b = c = d = nil
eval input ## NOT SECURE!
p a, b, c, d

__END__

Output:

2.4
[1, 0, 3.0, 5.0]
[5, 6, 11]
[[1, 2], [5, 6], [45, 55]]

ยทยทยท

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