Basically i have a document which I am opening and then i am reading
each line of the file and having to split it up into two arrays and then
into a hash in which i have to get some sort of output like this:
application/activemessage has no extensions
application/andrew-inset has extensions ez
application/applefile has no extensions
application/atom has extensions atom
application/atomcat+xml has extensions atomcat
application/atomicmail has no extensions
application/atomserv+xml has extensions atomsrv
application/batch-SMTP has no extensions
application/beep+xml has no extensions
application/cals-1840 has no extensions
I have determined that if there are no tabs in the document then the
file has no extension so what i did was an if statement in the beginning
to see if the line contained the tab if not then it would save false to
the position in the array that i was at in the each loop.
file.each_line do |line|
next if line[0] == ?#
next if line == "\n"
string = line
if string.include?("\t") == false
mimeValue[i] = false
mimeKey[i]=string.split
else
#THIS IS WHERE MY ISSUE IS NOW
mimeKey[i], mimeValue[i] = string.split("\t\t\t")
end
My problem now that sometimes teh document is split by tabs changing in
number one line may have 3 tabs other may have 5 and one might just have
just 1. So I am in a rut now How do i determine how many tabs are in
the line(string variable) thus so i can split the two parts into their
appropriate arrays. I was thinking I could do some kind of recurssion
which would test to see if tab and if so then add 1 to count and then be
able to do something like
Your tabs are consecutive and you don't actually care how many there are?
string.split(/\t+/)
?
···
On Sun, Sep 28, 2008 at 5:52 PM, Nick Bo <bornemann1@nku.edu> wrote:
#THIS IS WHERE MY ISSUE IS NOW
mimeKey[i], mimeValue[i] = string.split("\t\t\t")
My problem now that sometimes teh document is split by tabs changing in
number one line may have 3 tabs other may have 5 and one might just have
just 1.
incorrect if i do it that way then if i have 5 tabs in between the two
parts i want to separate then i get 4 blank arrays. giving me a total of
6 arrays.
eg = "abcdefg \t\t\t\t\t hi"
eg.split("\t) --> ["abcdefg ", "", "", "", " i"
eg.split("/\t+/) just gives me ["abcdefg \t\t\t\t\t i"] cause it dont
matche the pattern given to the split at all so it makes whole thing
part of the array.
eg = "abcdefg \t\t\t\t\t hi"
eg.split("\t) --> ["abcdefg ", "", "", "", " i"
eg.split("/\t+/) just gives me ["abcdefg \t\t\t\t\t i"] cause it dont matche the pattern given to the split at all so it makes whole thing part of the array.
eg = "abcdefg \t\t\t\t\t hi"
eg.split("\t) --> ["abcdefg ", "", "", "", " i"
eg.split("/\t+/) just gives me ["abcdefg \t\t\t\t\t i"] cause it dont
matche the pattern given to the split at all so it makes whole thing
part of the array.
Huh?
eg = "abcdefg \t\t\t\t\t hi"
=> "abcdefg \t\t\t\t\t hi"
eg.split(/\t+/)
=> ["abcdefg ", " hi"]
Regards,
Bill
it wouldnt give me the two, i so wish it did but i found a way around it
this is my solution and it works perfect
eg = "abcdefg \t\t\t\t\t\t hi"
splitArray = eg.split("\t")
splitArray = splitArray.delete("")
it wouldnt give me the two, i so wish it did but i found a way around it
this is my solution and it works perfect
eg = "abcdefg \t\t\t\t\t\t hi"
splitArray = eg.split("\t")
splitArray = splitArray.delete("")
IMO, the regex solution is better
splitArray = eg.split(/\t+/)
I think you put it in quotes. Leave the quotes out.